Hits: 5

# (C++ programming Example for Beginners)

# C++ Program to Check Whether a Number is Palindrome or Not

#### This program reverses an integer (entered by the user) using while loop. Then, if statement is used to check whether the reversed number is equal to the original number or not.

This program takes an integer from user and that integer is reversed.

If the reversed integer is equal to the integer entered by user then, that number is a palindrome if not that number is not a palindrome.

## Example: Check Palindrome Number

```
#include <iostream>
using namespace std;
int main(){
int n, num, digit, rev = 0;
cout << "Enter a positive number: ";
cin >> num;
n = num;
do
{
digit = num % 10;
rev = (rev * 10) + digit;
num = num / 10;
} while (num != 0);
cout << " The reverse of the number is: " << rev << endl;
if (n == rev)
cout << " The number is a palindrome.";
else
cout << " The number is not a palindrome.";
return 0;
}
```

**Output**

Enter a positive number: 12321 The reverse of the number is: 12321 The number is a palindrome.

Enter a positive number: 12331 The reverse of the number is: 13321 The number is not a palindrome.

In the above program, use is asked to enter a positive number which is stored in the variable `num`.

The number is then saved into another variable `n` to check it when the original number has been reversed.

Inside the do…while loop, last digit of the number is separated using the code `digit = num % 10;`

. This digit is then added to the `rev` variable.

Before adding the `digit` to `rev`, we first need to multiply the current data in the `rev` variable by 10 in order to add the digit to the n^{th} place in the number.

For example: in the number 123, 3 is in the zero^{th} place, 2 in the one^{th} place and 1 in the hundred^{th} place.

So, to add another number 4 after 123, we need to shift the current numbers to the left, so now 1 is in the thousand^{th} place, 2 in the one^{th} place, 3 is in the one^{th}place and 4 in the zero^{th} place.

This is done easily by multiplying 123 by 10 which gives 1230 and adding the number 4, which gives 1234. The same is done in the code above.

When the do while loop finally ends, we have a reversed number in `rev`. This number is then compared to the original number `n`.

If the numbers are equal, the original number is a palindrome, otherwise it’s not.

## C++ for Beginners: C++ Program to Check Whether a Number is Palindrome or Not

Disclaimer: The information and code presented within this recipe/tutorial is only for educational and coaching purposes for beginners and developers. Anyone can practice and apply the recipe/tutorial presented here, but the reader is taking full responsibility for his/her actions. The author (content curator) of this recipe (code / program) has made every effort to ensure the accuracy of the information was correct at time of publication. The author (content curator) does not assume and hereby disclaims any liability to any party for any loss, damage, or disruption caused by errors or omissions, whether such errors or omissions result from accident, negligence, or any other cause.The information presented here could also be found in public knowledge domains.