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# C++ Program to Add Two Distances (in inch-feet) System Using Structures

## Example: Add Distances Using Structures

``````
#include <iostream>
using namespace std;

struct Distance{
int feet;
float inch;
}d1 , d2, sum;

int main(){
cout << "Enter 1st distance," << endl;
cout << "Enter feet: ";
cin >> d1.feet;
cout << "Enter inch: ";
cin >> d1.inch;

cout << "nEnter information for 2nd distance" << endl;
cout << "Enter feet: ";
cin >> d2.feet;
cout << "Enter inch: ";
cin >> d2.inch;

sum.feet = d1.feet+d2.feet;
sum.inch = d1.inch+d2.inch;

// changing to feet if inch is greater than 12
if(sum.inch > 12)
{
++ sum.feet;
sum.inch -= 12;
}

cout << endl << "Sum of distances = " << sum.feet << " feet  " << sum.inch << " inches";
return 0;
}

``````

Output

```Enter 1st distance,
Enter feet: 6
Enter inch: 3.4

Enter information for 2nd distance
Enter feet: 5
Enter inch: 10.2

Sum of distances = 12 feet  1.6 inches
```

In this program, a structure `Distance` containing two data members (inch and feet) is declared to store the distance in inch-feet system.

Here, two structure variables d1 and d2 are created to store the distance entered by the user. And, the sum variables stores the sum of the distances.

The `if..else` statement is used to convert inches to feet if the value of inch of sum variable is greater than 12.

## C++ for Beginners: C++ Program to Add Two Distances

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