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## (Python Tutorials for Citizen Data Scientist)

# Python Program to Check Leap Year

#### In this program, you will learn to check whether a year is leap year or not. We will use nested if…else to solve this problem.

A leap year is exactly divisible by 4 except for century years (years ending with 00). The century year is a leap year only if it is perfectly divisible by 400. For example,

2017 is not a leap year 1900 is a not leap year 2012 is a leap year 2000 is a leap year

## Source Code

```
# Python program to check if year is a leap year or not
year = 2000
# To get year (integer input) from the user
# year = int(input("Enter a year: "))
if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
print("{0} is a leap year".format(year))
else:
print("{0} is not a leap year".format(year))
else:
print("{0} is a leap year".format(year))
else:
print("{0} is not a leap year".format(year))
```

**Output**

2000 is a leap year

You can change the value of `year` in the source code and run it again to test this program.

Excel formula for Beginners – How to get Sequence of years in Excel

## Python Examples for Beginners: Python Code to Check Leap Year

Disclaimer: The information and code presented within this recipe/tutorial is only for educational and coaching purposes for beginners and developers. Anyone can practice and apply the recipe/tutorial presented here, but the reader is taking full responsibility for his/her actions. The author (content curator) of this recipe (code / program) has made every effort to ensure the accuracy of the information was correct at time of publication. The author (content curator) does not assume and hereby disclaims any liability to any party for any loss, damage, or disruption caused by errors or omissions, whether such errors or omissions result from accident, negligence, or any other cause.The information presented here could also be found in public knowledge domains.

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