B-tree
In this tutorial, you will learn what a B-tree is. Also, you will find working examples of search operation on a B-tree in C.
B-tree is a special type of self-balancing search tree in which each node can contain more than one key and can have more than two children. It is a generalized form of the binary search tree.
It is also known as a height-balanced m-way tree.

Why B-tree?
The need for B-tree arose with the rise in the need for lesser time in accessing the physical storage media like a hard disk. The secondary storage devices are slower with a larger capacity. There was a need for such types of data structures that minimize the disk accesses.
Other data structures such as a binary search tree, avl tree, red-black tree, etc can store only one key in one node. If you have to store a large number of keys, then the height of such trees becomes very large and the access time increases.
However, B-tree can store many keys in a single node and can have multiple child nodes. This decreases the height significantly allowing faster disk accesses.
B-tree Properties
- For each node x, the keys are stored in increasing order.
- In each node, there is a boolean value x.leaf which is true if x is a leaf.
- If n is the order of the tree, each internal node can contain at most n – 1 keys along with a pointer to each child.
- Each node except root can have at most n children and at least n/2 children.
- All leaves have the same depth (i.e. height-h of the tree).
- The root has at least 2 children and contains a minimum of 1 key.
- If n ≥ 1, then for any n-key B-tree of height h and minimum degree
t ≥ 2
,h ≥ logt (n+1)/2
.
Operations
Searching
Searching for an element in a B-tree is the generalized form of searching an element in a Binary Search Tree. The following steps are followed.
- Starting from the root node, compare k with the first key of the node.
Ifk = the first key of the node
, return the node and the index. - If
k.leaf = true
, return NULL (i.e. not found). - If
k < the first key of the root node
, search the left child of this key recursively. - If there is more than one key in the current node and
k > the first key
, compare k with the next key in the node.
Ifk < next key
, search the left child of this key (ie. k lies in between the first and the second keys).
Else, search the right child of the key. - Repeat steps 1 to 4 until the leaf is reached.
Searching Example
- Let us search key
k = 17
in the tree below of degree 3.
B-tree - k is not found in the root so, compare it with the root key.
k is not found on the root node - Since
k > 11
, go to the right child of the root node.
Go to the right subtree - Compare k with 16. Since
k > 16
, compare k with the next key 18.
Compare with the keys from left to right - Since
k < 18
, k lies between 16 and 18. Search in the right child of 16 or the left child of 18.
k lies in between 16 and 18 - k is found.
k is found
Algorithm for Searching an Element
BtreeSearch(x, k)
i = 1
while i ≤ n[x] and k ≥ keyi[x] // n[x] means number of keys in x node
do i = i + 1
if i n[x] and k = keyi[x]
then return (x, i)
if leaf [x]
then return NIL
else
return BtreeSearch(ci[x], k)
To learn more about different B-tree operations, please visit
- Insertion on B-tree
- Deletion on B-tree
C Examples
// Searching a key on a B-tree in C
#include <stdio.h>
#include <stdlib.h>
#define MAX 3
#define MIN 2
struct BTreeNode {
int val[MAX + 1], count;
struct BTreeNode *link[MAX + 1];
};
struct BTreeNode *root;
// Create a node
struct BTreeNode *createNode(int val, struct BTreeNode *child){
struct BTreeNode *newNode;
newNode = (struct BTreeNode *)malloc(sizeof(struct BTreeNode));
newNode->val[1] = val;
newNode->count = 1;
newNode->link[0] = root;
newNode->link[1] = child;
return newNode;
}
// Insert node
void insertNode(int val, int pos, struct BTreeNode *node,
struct BTreeNode *child){
int j = node->count;
while (j > pos) {
node->val[j + 1] = node->val[j];
node->link[j + 1] = node->link[j];
j--;
}
node->val[j + 1] = val;
node->link[j + 1] = child;
node->count++;
}
// Split node
void splitNode(int val, int *pval, int pos, struct BTreeNode *node,
struct BTreeNode *child, struct BTreeNode **newNode){
int median, j;
if (pos > MIN)
median = MIN + 1;
else
median = MIN;
*newNode = (struct BTreeNode *)malloc(sizeof(struct BTreeNode));
j = median + 1;
while (j <= MAX) {
(*newNode)->val[j - median] = node->val[j];
(*newNode)->link[j - median] = node->link[j];
j++;
}
node->count = median;
(*newNode)->count = MAX - median;
if (pos <= MIN) {
insertNode(val, pos, node, child);
} else {
insertNode(val, pos - median, *newNode, child);
}
*pval = node->val[node->count];
(*newNode)->link[0] = node->link[node->count];
node->count--;
}
// Set the value
int setValue(int val, int *pval,
struct BTreeNode *node, struct BTreeNode **child){
int pos;
if (!node) {
*pval = val;
*child = NULL;
return 1;
}
if (val < node->val[1]) {
pos = 0;
} else {
for (pos = node->count;
(val < node->val[pos] && pos > 1); pos--)
;
if (val == node->val[pos]) {
printf("Duplicates are not permittedn");
return 0;
}
}
if (setValue(val, pval, node->link[pos], child)) {
if (node->count < MAX) {
insertNode(*pval, pos, node, *child);
} else {
splitNode(*pval, pval, pos, node, *child, child);
return 1;
}
}
return 0;
}
// Insert the value
void insert(int val){
int flag, i;
struct BTreeNode *child;
flag = setValue(val, &i, root, &child);
if (flag)
root = createNode(i, child);
}
// Search node
void search(int val, int *pos, struct BTreeNode *myNode){
if (!myNode) {
return;
}
if (val < myNode->val[1]) {
*pos = 0;
} else {
for (*pos = myNode->count;
(val < myNode->val[*pos] && *pos > 1); (*pos)--)
;
if (val == myNode->val[*pos]) {
printf("%d is found", val);
return;
}
}
search(val, pos, myNode->link[*pos]);
return;
}
// Traverse then nodes
void traversal(struct BTreeNode *myNode){
int i;
if (myNode) {
for (i = 0; i < myNode->count; i++) {
traversal(myNode->link[i]);
printf("%d ", myNode->val[i + 1]);
}
traversal(myNode->link[i]);
}
}
int main(){
int val, ch;
insert(8);
insert(9);
insert(10);
insert(11);
insert(15);
insert(16);
insert(17);
insert(18);
insert(20);
insert(23);
traversal(root);
printf("n");
search(11, &ch, root);
}
Searching Complexity on B Tree
Worst case Time complexity: Θ(log n)
Average case Time complexity: Θ(log n)
Best case Time complexity: Θ(log n)
Average case Space complexity: Θ(n)
Worst case Space complexity: Θ(n)
B Tree Applications
- databases and file systems
- to store blocks of data (secondary storage media)
- multilevel indexing
Python Example for Beginners
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