# Java Program to Find LCM of two Numbers

#### In this program, you’ll learn to find the lcm of two number by using GCD, and by not using GCD. This is done using for and while loops in Java.

The LCM of two integers is the smallest positive integer that is perfectly divisible by both the numbers (without a remainder).

## Example 1: LCM using while Loop and if Statement

```
public class Main{
public static void main(String[] args){
int n1 = 72, n2 = 120, lcm;
// maximum number between n1 and n2 is stored in lcm
lcm = (n1 > n2) ? n1 : n2;
// Always true
while(true) {
if( lcm % n1 == 0 && lcm % n2 == 0 ) {
System.out.printf("The LCM of %d and %d is %d.", n1, n2, lcm);
break;
}
++lcm;
}
}
}
```

**Output**

The LCM of 72 and 120 is 360.

In this program, the two numbers whose LCM is to be found are stored in variables `n1` and `n2` respectively.

Then, we initially set `lcm` to the largest of the two numbers. This is because, LCM cannot be less than the largest number.

Inside the infinite while loop (`while(true)`

), we check if `lcm` perfectly divides both `n1` and `n2` or not.

If it does, we’ve found the LCM. We print the LCM and break out from the while loop using `break`

statement.

Else, we increment `lcm` by 1 and re-test the divisibility condition.

We can also use GCD to find the LCM of two numbers using the following formula:

LCM = (n1 * n2) / GCD

If you don’t know how to calculate GCD in Java, check Java Program to find GCD of two numbers.

## Example 2: Calculate LCM using GCD

```
public class Main{
public static void main(String[] args){
int n1 = 72, n2 = 120, gcd = 1;
for(int i = 1; i <= n1 && i <= n2; ++i) {
// Checks if i is factor of both integers
if(n1 % i == 0 && n2 % i == 0)
gcd = i;
}
int lcm = (n1 * n2) / gcd;
System.out.printf("The LCM of %d and %d is %d.", n1, n2, lcm);
}
}
```

The output of this program is the same as Example 1.

Here, inside the for loop, we calculate the GCD of the two numbers – `n1` and `n2`. After the calculation, we use the above formula to calculate the LCM.

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