(C++ programming Example for Beginners)
C++ Program to Check Whether Number is Even or Odd
In this example, if…else statement is used to check whether a number entered by the user is even or odd.
To understand this example, you should have the knowledge of the following C++ programming topics:
- C++ if, if…else and Nested if…else
Integers which are perfectly divisible by 2 are called even numbers.
And those integers which are not perfectly divisible by 2 are not known as odd number.
To check whether an integer is even or odd, the remainder is calculated when it is divided by 2 using modulus operator %. If remainder is zero, that integer is even if not that integer is odd.
Example 1: Check Whether Number is Even or Odd using if else
#include <iostream>
using namespace std;
int main(){
int n;
cout << "Enter an integer: ";
cin >> n;
if ( n % 2 == 0)
cout << n << " is even.";
else
cout << n << " is odd.";
return 0;
}
Output
Enter an integer: 23 23 is odd.
In this program, if..else statement is used to check whether n%2 == 0 is true or not. If this expression is true, n is even if not n is odd.
You can also use ternary operators ?: instead of if..else statement. Ternary operator is short hand notation of if…else statement.
Example 2: Check Whether Number is Even or Odd using ternary operators
#include <iostream>
using namespace std;
int main(){
int n;
cout << "Enter an integer: ";
cin >> n;
(n % 2 == 0) ? cout << n << " is even." : cout << n << " is odd.";
return 0;
}
C++ for Beginners: C++ Program to Check Whether Number is Even or Odd
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